方法一、输入十六进制数
十六进制与十进制的转换关系: 一个十六进制Hex:0xA2C, 转换为十进制Dec = A(10)x162 + 2x16*1 + C(12)x160 。 具体代码如下:
#include
#include
using namespace std;
const int MAX = 100;
int DecArr[MAX] = { 0 };
/*首先对十六进制数0xA2C除16取余,即每次取一个数,并存入数组*/
/*这里不需要我们去处理A-F因为我们输入的就是十六进制数,计算机已经整数存储。*/
//十六进制转十进制
int Hex_Conversion_Dec(int aHex)
{
long Dec = 0;
int temp = 0;
int count = 0;
while (0 != aHex)//循环直至aHex的商为零
{
cout
Dec = Dec + DecArr[i];
}
else
{
//16左移4位即16²,左移8位即16³、以此类推。
Dec = (Dec + (DecArr[i]*(16 0 };
int Hex_Conversion_Dec(string aHex)
{
long Dec = 0;
int temp = 0;
int count = 0;
int DecCount = 0;
int strlen= aHex.length();
int StrLen = strlen;
while (strlen--)
{
if (aHex[count] '9' && aHex[count]'F'&&aHex[count]'f')
{
cout
DecArr[DecCount++] = aHex[count] - '0';
}
else if (aHex[count] >= 'A' && aHex[count]
DecArr[DecCount++] = aHex[count] - 'a' + 10;
}
count--;
}
int j = 0;
for (int i = 0; i
Dec = Dec + DecArr[i];
}
else
{
Dec = (Dec + (DecArr[i] * (16 |